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come on ....have a go

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in WR400F/426F/450F

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Guest Guest

Posted
Posted

You have two fuses. Each burns for 60 minutes.(Thats 120 for both).

The fuses burn at totally random rates, so for example cutting one in half wont give you 30 minutes.

using ONLY the two fuses and a means to light them, you have to time 45 minutes.

if youre interested ill give the answer tomorrow

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Guest Guest

Posted
Posted

and when youve done that.....

there are for people on one side of a bridge.

person 1 takes 10 minutes to cross, person 2 takes 5 minutes, person 3 takes 2 minutes and person 4 takes 1 minute

its dark, so they have to carry a torch, but they can only cross 2 at a time.

Any persons crossing the bridge must have the torch.

get all the people across in 17 minutes

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Guest Guest

Posted
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buzz off

why don't you make yourself useful and fix Fred's plug fouling problem?

i will only volunteer to figure your fuse problem if you hold the M-80 it's attached to in your hand till the 15 minutes is up

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Guest Guest

Posted
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there is a street with 100 street lamps. Each lamp has an on/off switch and all are switched off.

At the start of the street are 100 people. person 1's job is to go to every switch and switch it to its opposite position.

Person 2 set off and switches every second switch to its oppsite position. person 3 swtiches every third switch to its opposite position and so on.

What is the pattern of light that are on after the 100th person has been.

no paper allowed...this question was asked to me at my job inerview

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Grand Master

James_Dean

Posted
Posted

Taffy,

-the 5 and 10 minute guys cross together and let a faster 1 or 2 minute person bring the torch back for the last.

-If the fuse burns at 1 end it takes 60 minutes

-burn at 2 ends takes 30 (60/2)

-start burning on the ends and start it in the middle, and keep restarting to keep 4 flames going will take 15 minutes. (60/4)

-6 flames at a time takes 10 minutes (60/6)

-8 flames at a time takes 7.5 minutes (60/8)

I'm still wondering about Fred's plug fouling.

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Explorer

JKC

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And my all time favorite…

You and two fellow riders (Howard Huge and Mike from Silicone Valley) arrive at the Comfort Inn in Woodland Park and attempt to rent some rooms. The clerk claims only one room is remaining at the rate of $30/night. You each chip in $10 and head for much needed slumber. After determining that Howard and Mike are OK in sharing one of the only two beds, you all turn in.

Meanwhile, the front desk clerk is feeling guilty about charging you guys $30 for a room that normally goes for $25 so he summons the bellboy. He gives the bellboy five one-dollar bills with the instructions to return the money to the three of you.

While walking to the room, the bellboy frets over the fact that five is not divisible by three. He decides the easiest thing to do is stick two dollars in his pocket. Upon arriving at the room, the bellboy explains the overcharge mistake and returns one dollar to each of you.

The question is this: Each of you paid $10 and was given $1 in return for a net of $9 each. Right? $9 multiplied by the 3 of you equals $27 – Correct? Adding the $2 in the bellboy’s pocket gives a total of $29 –

Where did the other dollar go? ?

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Guest Guest

Posted
Posted

Duh! This sounds like politician math to me. The three dudes payed $25 for the room plus the $2 stolen by the bell hop. total of $27 or $9 each.

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